Methane has a heat of combustion of about

50 kJ/g. About how much heat would be
produced if 12 moles of methane were burned?
Methane has a molecular formula of CH4.

thank you bob 😳✨

molar mass CH4 is 16. 12 mols is 12*16 = 192 g

50 kJ/g x 192 g = ? kJ.

Well, to calculate the heat produced, we need to know the molar mass of methane.

The molar mass of carbon (C) is approximately 12 g/mol, and the molar mass of hydrogen (H) is about 1 g/mol. So, the molar mass of methane (CH4) would be:

(1 x 4) + 12 = 16 g/mol

Since we have 12 moles of methane, we can multiply the molar mass by the number of moles to get the total mass burned:

16 g/mol x 12 mol = 192 g

Now, with the heat of combustion of methane at 50 kJ/g, we can calculate the total heat produced by multiplying the mass burned by the heat of combustion:

192 g x 50 kJ/g = 9600 kJ

So, if we were to burn 12 moles of methane, approximately 9600 kJ of heat would be produced. That's enough to roast a lot of marshmallows!

To calculate the amount of heat produced when 12 moles of methane (CH4) are burned, we need to use the heat of combustion of methane.

The heat of combustion of methane is given as 50 kJ/g. However, we need to convert moles of methane to grams before we can proceed with the calculation.

To convert moles of methane to grams, we need to know the molar mass of methane. The molar mass of methane (CH4) can be calculated by summing the atomic masses of its constituent atoms:

Molar mass of C = 12.01 g/mol
Molar mass of H = 1.008 g/mol

Molar mass of CH4 = (12.01 g/mol) + 4*(1.008 g/mol)
= 16.04 g/mol

Now, we can calculate the mass of methane in grams. We know that 1 mole of methane has a mass of 16.04 grams.

Mass of 12 moles of methane = 12 moles * 16.04 g/mol
= 192.48 grams

Now that we have the mass of methane, we can calculate the heat produced by multiplying it by the heat of combustion:

Heat produced = Mass of methane * Heat of combustion
= 192.48 grams * 50 kJ/g
= 9624 kJ

Therefore, if 12 moles of methane were burned, approximately 9624 kJ of heat would be produced.