# Algebra

1.Solve the system of equations.
y = 2x^2 - 3
y = 3x - 1
a. no solution
b. (-1/2, 5), (2, -5/2)
c. (-1/2, -5/2), (2,5)
d. (1/2, 5/2), (2, 5)
2.how many real number solutions does the equation have 0 = -3x^2 + x - 4
a. 0
b. 1
c. 2
d. 3
3. solve the equation by completing the square. If necessary round to the nearest hundredth.
x^2 - 18x = 19
a. 1; 19
b. -1; 19
c. 3; 6
d. -3; 1
4. solve. x^2 - 81 = 0
a. 0
b. -9
c. -9, 9
d. 9
5. which model is most appropriate for the data shown in the graph below? (need wedsite to know the problem)
b. linear
c. exponential
d. line
for questions 6-9, match the equation to its corresponding graph.
(need wedsite to know the problem)
a, b, c, d
6. y=-2x^2+2
7. y=-x^2
8. y=2x^2
9. y=3x^2-4
Graph the quadratic functions y = -2x^2 and y = -2x^2 + 4 on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs.
(text box under question)

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1. i know this is cheating but i need the answers please

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2. Absolutely not!

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Writeacher
3. I will not give you the answers, but tell you what you have to do

1. y = 2x^2 - 3
y = 3x - 1
both right sides are equal to y, so they must be equal to each other
2x^2 - 3 = 3x - 1
2x^2 - 3x - 2 = 0
this factors nicely

2.
0 = -3x^2 + x - 4
3x^2 - x + 4 = 0 , a=3, b= -1, c = 4
b^2 - 4ac = 1 - 4(3)(4) = -47
you would be dealing with √-47 which is not a real number, so what do you think?

3. x^2 - 18x = 19
take half of the -18, square that, and add it to both the left and the right side.
x^2 - 18x + 81 = 19 + 81
(x-9)^2 = 100
carry on

4. x^2 - 81 = 0
difference of squares ...
(x+9)(x-9) = 0

and the solutions are .....

5. ...... ?

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Reiny
4. Here are the correct answers;
1. C (-1/2, -5/2), (2,5)
2. A 0
3. B -1;19
4. C -9,9
5. C Exponential
MATCHING
6. A
7. D
8. C
9. B
10. ESSAY

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5. y=3x+2
4x+2y=24

helppp

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