# Physics

A spiral spring of natural length of 20.0cm has a scale pan hanging freely on its lower end. When an object of mass 40g is placed in a pan. It length become 21.80cm when another object of mass 60g is placed in the pan the length becomes 22.05cm . Calculate the mass of the scale pan

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1. so a 20g increase (40 to 60g) caused a deformtion of (22.05-21.8) 0.75cm
f=kx or x= f/x=20/.75=80/3=2.66g/cm
now originally,
f=kx
(40-Masspan)=2.66g/cm * 1.80cm
solve for mass pan

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