Hi! I just want to clarify which formula would be best for this problem. Should I go with "V=Ed" or "V=kq/r"

The parallel plates of an air capacitor are separated by 2.25 mm. Each plate carries a charge of 6.50 nC. The magnitude of the electric field of the plates is 4.75x105 V/m. Find the potential difference between the plates.

as you fight your way against the electric field from one plate to the other the force on your charge q is a constant q E so the work done on a unit charge is E * distance = voltage

ohhh!! okay, it makes more sense now :) thank you!!

To solve this problem, you need to use the formula "V = Ed" because it relates the potential difference (V) to the electric field (E) and the distance between the plates (d).

In this case, you are given the values for the electric field (E = 4.75x10^5 V/m) and the distance between the plates (d = 2.25 mm). The charge (q) is not required to find the potential difference in this formula.

Now, let's calculate the potential difference (V):

V = Ed
= (4.75x10^5 V/m) * (2.25x10^-3 m)

To calculate this, you can multiply the two given values:

V = 1.06x10^3 V

Therefore, the potential difference between the plates is 1.06x10^3 V.