How would I solve this...........For each of the following unbalanced equations, calculate how many grams of each product would be produced by complete reaction of 12.5 g of the reactant indicated in boldface. Indicate clearly the mole ratio used for the conversion.
TiBr4(g) + H2 ⟶ Ti(s) + HBr(g)
To solve this problem, we need to follow a step-by-step approach:
1. Determine the balanced equation: We start by balancing the equation. In this case, we have:
TiBr4(g) + 2H2 ⟶ Ti(s) + 4HBr(g)
Now that the equation is balanced, we can move on to the next step.
2. Calculate the molar mass: Determine the molar mass of each compound involved in the reaction. The molar mass of TiBr4, H2, Ti, and HBr are:
- TiBr4: The molar mass of titanium (Ti) 47.867 g/mol + 4 times the molar mass of bromine (Br) 79.904 g/mol = 335.42 g/mol
- H2: 2 times the molar mass of hydrogen (H) 1.008 g/mol = 2.016 g/mol
- Ti: The molar mass of titanium (Ti) is 47.867 g/mol
- HBr: The molar mass of hydrogen (H) 1.008 g/mol + the molar mass of bromine (Br) 79.904 g/mol = 80.912 g/mol
3. Convert grams to moles: Use the molar mass to convert grams of reactant to moles. The molar mass allows us to convert the given 12.5 g of TiBr4 to moles.
Moles of TiBr4 = (Mass of TiBr4 in grams) / (Molar mass of TiBr4)
4. Set up mole ratio conversion: Use the balanced equation to set up the mole ratio conversion. From the balanced equation, we can see the following mole ratios:
1 mole of TiBr4 reacts to form 1 mole of Ti
1 mole of TiBr4 reacts to form 4 moles of HBr
We will use these mole ratios to calculate the moles of HBr produced.
5. Calculate moles of HBr produced: Now that we have the moles of TiBr4, we can use the mole ratios to calculate the moles of HBr produced.
Moles of HBr = (Moles of TiBr4) x (Mole ratio of HBr / Mole ratio of TiBr4)
6. Convert moles of HBr to grams: Use the molar mass of HBr to convert moles to grams.
Mass of HBr = (Moles of HBr) x (Molar mass of HBr)
By following this step-by-step approach, you should be able to calculate how many grams of each product would be produced by reacting 12.5 g of TiBr4.
TiBr4 + 2H2 ⟶ Ti + 4HBr
Don't know which reactant is in bold face, but I assume it is the TiBr4. If so, you have 12.5/367.483 = 0.034 moles.
So now just calculate the mass of the products in the ratio shown.