What is the length of the line segment with endpoints (5,−7) and (5, 11) ?
distance = square root of |(x2 - x1)^2 +(y2 - y1)^2
d = square root of {[5 -5}^2 +[11 - - 7}^2}
To find the length of a line segment with given endpoints, you can use the distance formula. The formula for finding the distance between two points (x1, y1) and (x2, y2) is:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the endpoints are (5, -7) and (5, 11). So, you can substitute the values into the distance formula:
distance = √((5 - 5)^2 + (11 - (-7))^2)
Simplifying further:
distance = √(0^2 + 18^2)
Calculating:
distance = √(0 + 324)
distance = √324
distance ≈ 18
Therefore, the length of the line segment with endpoints (5, -7) and (5, 11) is approximately 18 units.
To find the length of a line segment with given endpoints, you can use the distance formula. The formula for finding the distance between two points (x1, y1) and (x2, y2) in a 2D coordinate system is:
√((x2 - x1)^2 + (y2 - y1)^2)
In your case, the endpoints are (5, -7) and (5, 11). Let's substitute these values into the distance formula:
√((5 - 5)^2 + (11 - (-7))^2)
Simplifying the equation gives us:
√(0^2 + 18^2)
Which further simplifies to:
√(0 + 324)
Finally, taking the square root gives us:
√324 = 18
Therefore, the length of the line segment with endpoints (5, -7) and (5, 11) is 18 units.