a pile of bricks has 97 bricks in the first row, 91 bricks in the second row, 85 bricks in the third row, and so on until there is only one brick in the top row how many bricks are in the 15th row
well I guess we have an arithmetic sequence where a = 97 and d = -6
https://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
d + d(n-1)
97 - 6(14)
This is just an AP, with
A1 = 97
d = -6
and you want to find A15 = A1 + 14d
so plug in your numbers
97x 15=14x-6
Asan yung sagot
a pile of bricks has 97 bricks in the first row, 91 bricks in the second row, 85 bricks in the third row, and so on until there is only one brick in the top row how many bricks are in the 10th row
Well, it seems like the pile of bricks is playing a little game of "brickle-down" economics! Let's do some math magic to figure out how many bricks are in the 15th row.
We can see that the number of bricks in each row is decreasing by 6 each time. So, the pattern goes like this: 97, 91, 85, and so on.
To find the number of bricks in the 15th row, we can use a formula for the arithmetic series. The nth term of an arithmetic series is given by the formula:
nth term = first term + (n - 1) × common difference
In our case, the first term is 97 and the common difference is -6 (since each row has 6 fewer bricks than the previous row). Plugging in the values, we get:
15th term = 97 + (15 - 1) × (-6)
Calculating this expression, we find that the 15th term is 7.
So, ta-da! There are 7 bricks in the 15th row. Just don't juggle them, unless you're a professional brick juggler!
To determine the number of bricks in the 15th row, we can observe the pattern.
If we look closely, each row decreases by 6 bricks compared to the previous row. So, we can calculate the number of bricks in each row using the formula:
Number of bricks in nth row = (First row - (n-1) * 6)
Using this formula, we can calculate the number of bricks in the 15th row as follows:
Number of bricks in 15th row = (97 - (15-1) * 6)
= (97 - 14 * 6)
= (97 - 84)
= 13
Therefore, there are 13 bricks in the 15th row.