The sum of two consecutive numbers divided by their positive difference is equal to 9 . find the smaller number.
smaller number ---- x
next consecutive integer --- x+1
(x + x+1)/((x+1 - x) = 9
2x + 1 = 9
...
take over
4 and 5
Good thank for your help
To find the smaller number, let's consider two consecutive numbers. Let's call the smaller number "x" and the larger number "x + 1" (since they are consecutive).
According to the problem, the sum of these two numbers divided by their positive difference is equal to 9. Mathematically, this can be written as:
(x + (x + 1)) / |x - (x + 1)| = 9
Simplifying the equation, we have:
(2x + 1) / |-1| = 9
(2x + 1) / 1 = 9
2x + 1 = 9
2x = 9 - 1
2x = 8
x = 8 / 2
x = 4
Therefore, the smaller number is 4.