Good morning. This is a repost. The system is telling me my calculations is incorrect. I thought a fresh pair of eyes would help. Please tell me what I am doing wrong.

Suppose a monatomic ideal gas is contained within a vertical cylinder that is fitted with a movable piston. The piston is frictionless and has a negligible mass. The area of the piston is 3.06 10-2 m2, and the pressure outside the cylinder is 1.02 105 Pa. Heat (2109 J) is removed from the gas. Through what distance does the piston drop?

For Further Reading

Physics HELP!!!!!!!! - bobpursley, Tuesday, April 17, 2007 at 9:29am
PV=work
V= area *distance

You know P, area, and work. Solve for distance.

According to the formula provided
PV=work
P(area x distance)= work

solve for distance

distance = work - P/ area

this is where it get confusing for me

P= 1.02 x 10^5 Pa
A= 3.06 x 10^-2 m^2
W= ? I am unsure how to get he value of work

For Further Reading

Physics, still don't get it! - bobpursley, Wednesday, April 18, 2007 at 10:38pm
Work is heat, and heat is work. It was given.

Physics, still don't get it! - Mary, Wednesday, April 18, 2007 at 11:10pm
Please check my working out. The system is saying it is wrong.

PV = W

PV = 2109J

V = 2109J/ 1.02 X 10^5Pa

V = 0.020676471m^3

Area x distance = 0.020676471m^3

distance = 0.020676471/ 3.06 x 10^-2m^2

distance = 0.6757 m

Physics, still don't get it! - bobpursley, Wednesday, April 18, 2007 at 11:16pm
I don't see anything wrong.

To calculate the distance the piston drops, you need to use the equation PV = work, where P is the pressure, V is the volume, and work is the amount of heat transferred. Rearranging the equation to solve for distance, you get V = area * distance. Here's how you can find the distance:

1. Start with the equation PV = work. Plug in the given values:
P = 1.02 x 10^5 Pa (pressure outside the cylinder)
V = unknown (volume)
work = 2109 J (heat removed from the gas)

2. Solve for V by dividing both sides of the equation by P:
V = work / P

3. Substitute the given values to find V:
V = 2109 J / (1.02 x 10^5 Pa)

4. Calculate the value of V in cubic meters. Make sure you convert the pressure from pascals to cubic meters by using the appropriate conversion factor. Let's assume 1 J = 1 m^3 (this is only an assumption for simplicity):
V = 2109 J / (1.02 x 10^5 Pa)
V ≈ 0.020676471 m^3

5. Use the equation V = area * distance and solve for distance. Rearrange the equation to solve for distance:
distance = V / area

6. Substitute the values for V and area:
distance = 0.020676471 m^3 / (3.06 x 10^-2 m^2)

7. Calculate the value of distance by dividing the volume by the area:
distance ≈ 0.6757 m

Therefore, the distance the piston drops is approximately 0.6757 meters.