in the 74 s after lift-off, the shuttle challenger travels 36 km. assume constant acceleration, calculate

a) the acceleration of the shuttle in m/s^2.

b) the speed of the shuttle in km/h after 74s.

a) d = 1/2 a t^2 ... 36 = 1/2 a 74^2

b) it starts from rest ... so , v = 2 (36 km / 74 s)
... convert km/s to km/hr ... multiply by 3600 s/hr

a) Well, the shuttle sure is a go-getter! To calculate its acceleration in m/s^2, we can use the formula:

acceleration = velocity / time

Since we have the distance (36 km) and time (74 s), we first need to convert the distance to meters:

36 km * 1000 = 36,000 meters

Now, let's plug in the numbers:

acceleration = 36,000 m / 74 s ≈ 486.49 m/s^2

So, the acceleration of the shuttle is approximately 486.49 m/s^2.

b) To find the speed of the shuttle in km/h after 74 seconds, let's use the formula:

speed = acceleration * time

But hold on a minute, we need to convert the acceleration to km/h^2. We can achieve that by multiplying the acceleration by 3.6:

acceleration (km/h^2) = 486.49 m/s^2 * 3.6 = 1753.76 km/h^2

Now, let's find the speed:

speed = 1753.76 km/h^2 * 74 s ≈ 129,698.24 km/h

So, the speed of the shuttle after 74 seconds is approximately 129,698.24 km/h. Let's just hope it didn't pass any speed limits up there!

To solve this problem, we will use the following equations of motion:

1. Velocity (v) = initial velocity (u) + acceleration (a) * time (t)
2. Displacement (s) = initial velocity (u) * time (t) + 0.5 * acceleration (a) * time^2

Given:
Displacement (s) = 36 km = 36,000 m
Time (t) = 74 s

a) To find the acceleration (a), we will use equation (2). Rearranging the equation, we get:

a = (s - u * t) / (0.5 * t^2)

Since we are assuming constant acceleration, the initial velocity (u) can be assumed to be zero for this calculation.

a = (36,000 m - 0 m * 74 s) / (0.5 * (74 s)^2)
a = 36,000 m / (0.5 * 5476 s^2)
a ≈ 13.13 m/s^2

Therefore, the acceleration of the shuttle is approximately 13.13 m/s^2.

b) To find the speed of the shuttle in km/h after 74 s, we will use equation (1). Rearranging the equation, we get:

v = u + a * t

Since the initial velocity (u) is zero, the equation simplifies to:

v = a * t

Converting the time from seconds to hours:

t (hours) = 74 s * (1 min / 60 s) * (1 hr / 60 min)
t (hours) ≈ 0.034722 hr

Substituting the values into the equation:

v = 13.13 m/s^2 * 0.034722 hr * (3600 s / 1 hr) * (1 km / 1000 m)
v ≈ 16.82 km/h

Therefore, the speed of the shuttle after 74 s is approximately 16.82 km/h.

To calculate the acceleration of the shuttle, we can use the formula:

Acceleration (a) = (Change in velocity) / (Change in time)

In this case, the shuttle traveled 36 km in 74 seconds. First, we need to convert the distance traveled from kilometers to meters:

Distance travelled = 36 km = 36,000 m.

Now, we have the values needed to calculate the acceleration:

Change in velocity = Distance travelled = 36,000 m
Change in time = 74 s

a) Acceleration:
Acceleration (a) = (Change in velocity) / (Change in time)
Acceleration (a) = 36,000 m / 74 s

To get the acceleration in m/s², divide the distance by the time:
a ≈ 486.49 m/s²

b) To calculate the speed of the shuttle in km/h after 74 seconds, we need to use the formula:

Speed = Initial speed + (Acceleration x Time)

Given that the initial speed is not provided, we assume the shuttle starts from rest (0 km/h).

Initial speed = 0 km/h

Using the acceleration calculated in part a (486.49 m/s²) and the time of 74 seconds:

Time = 74 s

First, we need to convert acceleration from meters per second squared (m/s²) to kilometers per hour squared (km/h²):

Acceleration = 486.49 m/s²
Acceleration = 486.49 * (3600/1000)^2 km/h²
Acceleration ≈ 486.49 * 12.96 km/h²
Acceleration ≈ 6309.01704 km/h²

Next, we substitute the values into the formula:

Speed = Initial speed + (Acceleration x Time)
Speed = 0 km/h + (6309.01704 km/h² x 74 s)

To get the speed of the shuttle in km/h, multiply the acceleration by the time and add it to the initial speed:

Speed ≈ 0 + (6309.01704 km/h² x 74)
Speed ≈ 466,236.261 km/h

Therefore, the speed of the shuttle in km/h after 74 seconds is approximately 466,236.261 km/h.