A body weigh of 0.26N in air. When total emmers in water weight 0.16h and 0.18n in another liquid. Calculate the relative density of of liquid
what is its volume v?
rho g v = force up from water = 1000 kg/m^3 * 9.81 * v
that is the change in weight from air to water
9810 v = .26 - .16 = .1 n
so
v = .1 / 9810 meters^3
now
rho g V = .26 - .18 = .08
rho *9.81 * .1/9810 = .08
rho = .8 (9810/9.81)
but it asked for "relative" density so we want rho/water density = rho/1000
well that is 0.8