Are these correct now Mr reiny?
What is the solution of x² + 64 = 0?
A. –5
B. 8***
C. ±8
D. no solution
What is the value of b in the triangle shown below?
A right triangle is shown. The height equals 3 b. The base equal b. The area of the triangle equals 24 square inches squared.
A. –4 in
B. 4 in
C. ±4 in***
D. no solution
#2 is correct : )
Yes : )
#1 is incorrect.
Either you factor to solve it...
Or take the 64 to the other side, then take the square root...
So B is NOT correct...
1: ±8
2: 4
are those correct now?
Can you take the square root of a negative number?
You have x^2 = -64
so you try to take the square root of both sides...
no i cant take the square root of a negative number so its no solution!
did i get it right Ms pi?
For the first question, you have the equation x² + 64 = 0. To find the solutions, we can start by subtracting 64 from both sides to get x² = -64.
Taking the square root of both sides gives us x = ±√(-64).
Since the square root of a negative number is not a real number, this equation has no real solutions. Therefore, the correct answer is D. no solution.
For the second question, we have a right triangle with height equal to 3b and base equal to b. The formula for the area of a triangle is A = (1/2) * base * height.
Substituting the given values, we get 24 = (1/2) * b * (3b). Simplifying this equation gives us 24 = (3/2) * b².
To solve for b, we can multiply both sides by (2/3) to isolate b². This gives us b² = (2/3) * 24, which simplifies to b² = 16.
Taking the square root of both sides, we get b = ±√16.
The square root of 16 is 4, so the correct answer is C. ±4 in.