Solve each equation by finding square roots. If the equation has no real-number solution, write no solution. 4g^2=25
In the equation when i divide 25 by 4 why do i keep it as 25/4 threw out solving the rest of the problem? why not change it to 4??? I'm really struggling on understanding these...
taking square root ... 2 g = ± 5 ... g = ± 5/2
keep the 25/4 because that makes taking the square root easier.
After you take the square root of each part of the fraction you will have 5/2
oh that makes sense, thank u!
I wasn't asking for the answer R_scott but thanks anyway
In the equation 4g^2 = 25, the objective is to find the value of g that satisfies the equation. One way to solve this equation is by finding the square roots.
To start, let's isolate the g^2 term by dividing both sides of the equation by 4:
(4g^2)/4 = 25/4
Simplifying, we get:
g^2 = 25/4
Now, let's solve for g by finding the square root of both sides of the equation. However, when taking the square root, it's important to consider both the positive and negative square roots.
√(g^2) = √(25/4)
Since squaring a number always results in a positive value, we can drop the square root sign on the left side and just write g:
g = ±√(25/4)
Note that the ± symbol represents both the positive and negative solutions.
Now, let's simplify the square root of 25/4. To do this, the square root can be taken separately for the numerator and denominator:
g = ±(√25)/(√4)
Simplifying further, we have:
g = ±(5/2)
Therefore, the solutions to the equation 4g^2 = 25 are g = 5/2 and g = -5/2.