An ideal solution made up of benzene (C6H6) and Toluene (C6H5CH3) has mole fraction of benzene as 0,0.25,0.5,0.75 and 1.0 at various concentrations
My crystal ball is hazy today. It isn't telling me what question you are asking.
1)Calculate the molar fractions of toluene
2)calculate the respective partial vapour pressures of benzene and toluene given that the pure vapour pressure are 3.6 x 10 and 1.12 x 104 Nm² for benzene and toluene respectively.
3)calculate the total vapour pressure of the solution at this concentrations.
4) plot on one graph paper a fully labeled vapour pressure composition curve for the ideal solution.
5)freely discuss your graph
To calculate the concentrations of benzene (C6H6) and toluene (C6H5CH3) in the ideal solution, we can use the concept of mole fraction.
The mole fraction of a component in a mixture is defined as the ratio of moles of that component to the total moles of all components in the mixture.
Given that the ideal solution is made up of benzene (C6H6) and toluene (C6H5CH3), we can consider the total moles of both components together in the mixture as 1 mole.
Let's calculate the concentrations of benzene and toluene for different mole fractions:
1. For a mole fraction of benzene (C6H6) = 0:
Since the total moles of both components together is 1 mole, the mole fraction of toluene (C6H5CH3) will be 1 - 0 = 1 mole.
So, for a mole fraction of benzene = 0, the concentration of benzene is 0 moles and the concentration of toluene is 1 mole.
2. For a mole fraction of benzene (C6H6) = 0.25:
The mole fraction of toluene (C6H5CH3) will be 1 - 0.25 = 0.75 moles.
So, for a mole fraction of benzene = 0.25, the concentration of benzene is (0.25 * 1 mole) = 0.25 moles and the concentration of toluene is (0.75 * 1 mole) = 0.75 moles.
3. For a mole fraction of benzene (C6H6) = 0.5:
The mole fraction of toluene (C6H5CH3) will be 1 - 0.5 = 0.5 moles.
So, for a mole fraction of benzene = 0.5, the concentration of benzene is (0.5 * 1 mole) = 0.5 moles and the concentration of toluene is (0.5 * 1 mole) = 0.5 moles.
4. For a mole fraction of benzene (C6H6) = 0.75:
The mole fraction of toluene (C6H5CH3) will be 1 - 0.75 = 0.25 moles.
So, for a mole fraction of benzene = 0.75, the concentration of benzene is (0.75 * 1 mole) = 0.75 moles and the concentration of toluene is (0.25 * 1 mole) = 0.25 moles.
5. For a mole fraction of benzene (C6H6) = 1.0:
Since the total moles of both components together is 1 mole, the mole fraction of toluene (C6H5CH3) will be 1 - 1 = 0 moles.
So, for a mole fraction of benzene = 1.0, the concentration of benzene is 1 mole and the concentration of toluene is 0 moles.
By using the concept of mole fraction, we can determine the concentrations of benzene and toluene in the ideal solution for different mole fractions.