A mass, hung on a string which is wrapped around an axel on a wheel, produces a tension in the string of 5.69N. The axel has a radius of 0.045m. The wheel has a mass of 4.00kg and a radius of 0.125m. What is the torque produced by the tension on the axel?
Well, I'll do my best to calculate that for you, but expect a bit of clowning around along the way!
First, let's calculate the force of tension generated by the mass. You mentioned it's 5.69N. Now, let's move on to the torque!
Torque is calculated by multiplying the force applied with the distance from the axis of rotation. In this case, the axis of rotation is the axle, and we have the dimensions of the wheel, so we're good to go!
The distance from the axis of rotation is the radius of the axle, which is given as 0.045m. So, the torque can be calculated by multiplying the force of tension (5.69N) with the radius (0.045m). Mathematically, it's torque = force × distance.
Let's plug in the values and calculate the torque: torque = 5.69N × 0.045m = 0.25605 N·m.
So, the torque produced by the tension on the axle is approximately 0.25605 N·m.
And there you have it! A serious answer with just a dash of clowning around. I hope it made you smile!
To calculate the torque produced by the tension on the axel, we need to use the formula:
Torque = Force * Lever Arm
In this case, the force is the tension in the string (5.69 N), and the lever arm is the distance from the center of the axel to where the force is applied.
The lever arm can be found by calculating the difference between the radii of the wheel and the axel:
Lever Arm = Radius of the wheel - Radius of the axel
Substituting the given values:
Lever Arm = 0.125 m - 0.045 m
Lever Arm = 0.080 m
Now we can calculate the torque:
Torque = Force * Lever Arm
Torque = 5.69 N * 0.080 m
Torque ≈ 0.4552 N·m
Therefore, the torque produced by the tension on the axel is approximately 0.4552 N·m.
To calculate the torque produced by the tension on the axle, we can use the formula:
Torque = Force x Perpendicular distance
The force in this case is the tension in the string, which is given as 5.69N.
The perpendicular distance is the distance between the point where the force is applied (the axle) and the axis of rotation (the center of the wheel). In this case, it is the radius of the axle.
Now, let's plug in the values:
Torque = 5.69N x 0.045m
Multiply 5.69N by 0.045m:
Torque = 0.25605 Nm
Therefore, the torque produced by the tension on the axle is 0.25605 Nm.