Let f(x)=x^2+2 and g(x)=1−3x. Find each function value:
(f−g)(2)
f(2) - g(2) = 2^2 + 2 - [1 - (3 * 2)]
To find the value of (f - g)(2), we need to subtract the function g(x) from the function f(x) and then evaluate it at x = 2.
First, let's find the value of f(x) by substituting x = 2 into the function f(x):
f(x) = x^2 + 2
f(2) = (2)^2 + 2
f(2) = 4 + 2
f(2) = 6
Next, let's find the value of g(x) by substituting x = 2 into the function g(x):
g(x) = 1 - 3x
g(2) = 1 - 3(2)
g(2) = 1 - 6
g(2) = -5
Now, we can find the value of (f - g)(2) by subtracting g(2) from f(2):
(f - g)(2) = f(2) - g(2)
(f - g)(2) = 6 - (-5)
(f - g)(2) = 6 + 5
(f - g)(2) = 11
Therefore, the value of (f - g)(2) is 11.