Log√35 - log√7 + log√2
Log√35 - log√7 + log√2
= log (35)^(1/2) - log 7^(12) + log 2^(1/2)
= (1/2)log 35 - (1/2)log 7 + (1/2)log 2
= (1/2)(log 35 - log7 + log 2)
= (1/2)log(35/7*2)
= (1/2) log 10
= (1/2)(1)
= 1/2
I don't understand this maths
Log√35 × √2 ÷ √7
Log √70 ÷ √7
=√10
Log√10
=1÷2 log 10
1×1÷2×2
=1/2
I still don't understand please explain
Please help me solve log √35 base 10 - log √7 base 10 + log √12 base 10
1/2
To solve the expression log√35 - log√7 + log√2, we can start by using some properties of logarithms. The first property we will use is the logarithmic identity:
log(a) - log(b) = log(a/b)
Applying this identity to our expression, we have:
log√35 - log√7 + log√2 = log(√35 / √7) + log√2
Simplifying further, we can simplify the square roots:
√35 = √(5 * 7) = √5 * √7
√7 = √7
√2 = √2
Now the expression becomes:
log(√5 * √7 / √7) + log√2
Since √7/√7 simplifies to 1, the expression further simplifies to:
log(√5) + log√2
Next, we can use another logarithmic identity:
log(a) + log(b) = log(a * b)
Applying this identity to our expression, we have:
log(√5) + log√2 = log(√5 * √2)
Simplifying further, we have:
√5 * √2 = √10
Now the expression becomes:
log(√10)
Therefore, the value of log√35 - log√7 + log√2 is log(√10).