A total of 547 adult and student tickets were sold for a high school musical. The ticket prices were $10 for adults and $5 for students. A total of $3,775 was collected from ticket sales. How many adult and student tickets were sold?
Thanks, I got it.
The answer should be D.
To find the number of adult and student tickets sold, we can set up a system of equations using the given information.
Let's denote the number of adult tickets as 'A' and the number of student tickets as 'S'.
From the problem, we can establish two equations based on the given information:
Equation 1: A + S = 547 (total number of adult and student tickets sold)
Equation 2: 10A + 5S = 3775 (total amount collected from ticket sales)
To solve this system of equations, we can use a method called substitution or elimination.
Let's use the substitution method:
From Equation 1, we can rewrite it as A = 547 - S.
Substitute this value of A into Equation 2:
10(547 - S) + 5S = 3775
Now, distribute and simplify:
5470 - 10S + 5S = 3775
Combine like terms:
-5S = -1695
Divide both sides by -5:
S = 339
Now, substitute this value of S back into Equation 1 to find A:
A + 339 = 547
A = 547 - 339
A = 208
Therefore, 208 adult tickets and 339 student tickets were sold.
Count the tickets and the money:
a+s = 547
10a+5s = 3775
Now just solve for a and s