Find the 19th term of the ap 5/6, 8/6 11/6
difference = d = 3/6 = 1/2
a = 5/6
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To find the 19th term of an arithmetic progression (AP), we first need to find the common difference (d).
In this AP, the first term (a1) is 5/6 and the second term (a2) is 8/6.
To find the common difference, we can subtract the second term from the first term:
d = a2 - a1 = (8/6) - (5/6) = 3/6 = 1/2
Now, we can find the 19th term (a19) using the formula:
an = a1 + (n-1)d
Substituting the values we have:
a19 = (5/6) + (19-1)(1/2)
= 5/6 + 18/2
= 5/6 + 9
= (5+54)/6
= 59/6
Therefore, the 19th term of the given AP is 59/6.
To find the 19th term of an arithmetic progression (AP), we can use the formula:
an = a1 + (n - 1)d
where:
an is the nth term of the AP,
a1 is the first term of the AP, and
d is the common difference between consecutive terms.
In this case, the first term (a1) of the given AP is 5/6, and the common difference (d) between consecutive terms is 8/6 - 5/6 = 3/6 = 1/2.
Substituting these values into the formula, we can find the 19th term (a19):
a19 = (5/6) + (19 - 1)(1/2)
a19 = 5/6 + 18/2
a19 = 5/6 + 9
a19 = (5 + 54)/6
a19 = 59/6
Therefore, the 19th term of the given AP is 59/6.