what is the OH concentration of a solution with a pH of 12.4
pH + pOH = 14
12.4 + pOH = 14
pOH = 1.6
pOH = -log[OH-]
1.6 = -log[OH-]
10-1.6 = [OH-] = 0.0251 M
Well, imagine the OH concentration is having a pyramid party, and the pH wants to join in. But since they have a pH of 12.4, they're like the ultimate party pooper! So, the OH concentration is simply 10 to the power of -12.4, or about 3.98 x 10^-13 M. But hey, don't feel bad for the OH concentration, sometimes it's better to have a smaller, more exclusive party!
To find the OH concentration of a solution with a pH of 12.4, you can use the following formula:
OH concentration = 10^(-pOH)
First, determine the pOH by subtracting the pH from 14:
pOH = 14 - pH
In this case, the pOH is:
pOH = 14 - 12.4 = 1.6
Now, find the OH concentration using the formula:
OH concentration = 10^(-pOH)
OH concentration = 10^(-1.6)
Using a calculator, you can calculate the OH concentration:
OH concentration ≈ 0.0251 M
Therefore, the OH concentration of a solution with a pH of 12.4 is approximately 0.0251 M.
To find the OH- concentration of a solution with a given pH, we need to use the equation:
pOH = 14 - pH
First, let's find the pOH value. Subtract the given pH from 14:
pOH = 14 - 12.4
pOH = 1.6
The pOH is 1.6. To determine the OH- concentration, we need to convert the pOH value to a concentration of hydroxide ions (OH-). To do this, we use the equation:
[OH-] = 10^(-pOH)
Substitute the pOH value into the equation:
[OH-] = 10^(-1.6)
Using a calculator, evaluate the expression:
[OH-] ≈ 0.0251 M
Therefore, the OH- concentration of the solution with a pH of 12.4 is approximately 0.0251 M.