A regular square pyramid has a height of 2 and lateral edges of length 10. What is the volume of the pyramid?

oops ...

(192 * 2) / 3

(10^2 * 2) / 3

lateral edges, not base edges.

To find the volume of a regular square pyramid, you can use the formula: V = (1/3) * B * h, where V represents the volume, B represents the area of the base, and h represents the height of the pyramid.

In this case, the base of the pyramid is a square. The pyramids' lateral edges form the slant height of each triangular face of the pyramid. Since the pyramid is regular, the slant height is equal to the lateral edge length.

Given that the lateral edges have a length of 10, we can use this value as the side length of the base square. The area of a square is calculated as B = a², where a is the length of each side.

Therefore, the area of the base is B = (10)² = 100 square units.

Now, with the height of the pyramid given as 2, we can substitute the values into the volume formula:

V = (1/3) * 100 * 2
V = (1/3) * 200
V = 200/3

Hence, the volume of the regular square pyramid is 200/3 cubic units.