Which conversion factor should be used to solve the following problem?
How many moles of water (H2O) would be produced from the reaction of 3.25 moles of hydrochloric acid (HCl) reacting with excess calcium hydroxide Ca(OH)2?
Ca(OH)2 +2HCl --> CaCl2 + 2H2O
3.25 mol HCL x ?
Question options:
2 mol HCl / 2 mol H2O
2 mol H2O / 2 mol HCl
2 mol HCl / 1 mol CaCl2
1 mol CaCl2 / 2 mol HCl
HCl x H2O/HCl = H2O
Just like any other units that cancel.
And the equation says the ratio is 2:2
So, what do you think?
To solve this problem, we need to use the molar ratio from the balanced chemical equation. The balanced equation shows that for every 2 moles of HCl reacted, 2 moles of water (H2O) are produced.
Thus, the correct conversion factor to use is:
2 mol H2O / 2 mol HCl
Therefore, the answer is option: 2 mol H2O / 2 mol HCl.
To solve this problem, we need to determine the conversion factor that relates the number of moles of hydrochloric acid (HCl) to the number of moles of water (H2O) in the balanced chemical equation.
From the balanced equation:
Ca(OH)2 + 2HCl --> CaCl2 + 2H2O
We can see that for every 2 moles of HCl, 2 moles of H2O are produced. Therefore, the conversion factor we should use is:
2 mol H2O / 2 mol HCl
So, the correct answer is:
2 mol H2O / 2 mol HCl