If the measure of angle A is doubled and then decreased by 10 while the complement of angle A is decreased by one-third of itself, then these two anlges formed are still complementary. Find the supplement of angle A.
Please explain so i could understand. thank you !
Isn't this statement the same as
(2*A - 10) + (2/3)(90-A)=90
Then you want the supplement of A after you solve for A.
check my thinking.
whats ur email address..im jane
Ok, what do we know about supplements and complements? Suppose we're given angle A (in degrees). Let's denote it's supplement by A" and it's complement by A'. Then we know
A + A" = 180 and A + A' = 90.
The problem you have states:
"If the measure of angle A is doubled and then decreased by 10 while the complement of angle A is decreased by one-third of itself, then these two anlges formed are still complementary. Find the supplement of angle A."
We need to convert the words into algebraic equations we can solve. This is probabaly the most difficult part of the problem in my opinion.
We're told A is doubled and decreased by 10. This means we have
while A' decreased by 1/3. Thus
(2) A' - (1/3)A'=(2/3)A' We're then told that if we add (1) and (2)
2A-10 + (2/3)A' = 90 (they're still complimentary)
We now have a system of equations:
A + A' =90
2A-10 + (2/3)A' = 90
Do you know how to solve a system of equations? If not, or you're stuck, I'll provide more help, but I need you to show some work too.
After you find angle A there should be no trouble finding the complement.
I need help in solving a graphing equation. this is the problem x+3y<6
and x>-4 and y(is greater or equal to) 2x-5
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