A balloon contains 40.0 L of helium gas at 106.2 kPa. What is the volume of the helium when the balloon rises to an altitude where the pressure is only 35.0 kPa? (Assume that the temperature remains constant.)
Please show work! I am NOT a science person, and am barely passing chemistry class :(
P1V1 = P2V2
Substitute the numbers and solve. Post your work if you get stuck.
so what would the equation be? im stuck on which is which
To solve this problem, we can use the combined gas law, which states:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure = 106.2 kPa
V1 = initial volume = 40.0 L
T1 = initial temperature (constant)
P2 = final pressure = 35.0 kPa
V2 = final volume (what we need to find)
T2 = final temperature (constant)
Since the temperature remains constant, we can cancel it out:
(P1 * V1) / T1 = (P2 * V2) / T2
(P1 * V1) = (P2 * V2)
(V2) = (P1 * V1) / P2
Now, we can substitute the given values into the equation to find V2:
V2 = (106.2 kPa * 40.0 L) / 35.0 kPa
First, let's cancel out the units:
V2 = (106.2 * 40.0) / 35.0 L
Next, we can calculate the result:
V2 = 122.62857142857143 L
Therefore, when the balloon rises to an altitude where the pressure is only 35.0 kPa, the volume of the helium gas will be approximately 122.6 L.
To solve this problem, you can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional, assuming the temperature remains constant.
Boyle's Law formula is: P1 * V1 = P2 * V2
P1: Initial pressure of the gas (106.2 kPa)
V1: Initial volume of the gas (40.0 L)
P2: Final pressure of the gas (35.0 kPa)
V2: Final volume of the gas (unknown)
Rearrange the formula to solve for V2:
V2 = (P1 * V1) / P2
Now, substitute the given values into the formula:
V2 = (106.2 kPa * 40.0 L) / 35.0 kPa
Note: It's important to ensure that the pressure units cancel out, leaving you with the desired volume unit (in this case, liters).
Now, calculate:
V2 = (4248 L * kPa) / kPa
V2 = 121.4 L
Therefore, when the balloon rises to an altitude where the pressure is 35.0 kPa, the volume of the helium gas will be approximately 121.4 liters.