Make a table to show the sample space and find the number of outcomes. Then find the probability.
A theater uses a letter to show which row a seat is in, and a number to show the column. If there are eight rows and ten columns, what is the probability that you select a seat at random that is in column 1?
The favorable outcomes would be A1, B1, C1, D1, E1, F1, G1, and H1. The number is: 8
It should be very easy to make a table.
_
Probability): 8 x 10 = 80 and there is 8 favorable outcomes so: 8/80 = 1/10
1 ÷ 10 = 0.1
0.1 x 100 = 10 % is the probability.
To find the probability of selecting a seat at random that is in column 1, we first need to create a table to represent the sample space.
Let's create a table with eight rows and ten columns representing the potential seats in the theater:
| | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
|---|---|---|---|---|---|---|---|---|---|----|
| A | | | | | | | | | | |
| B | | | | | | | | | | |
| C | | | | | | | | | | |
| D | | | | | | | | | | |
| E | | | | | | | | | | |
| F | | | | | | | | | | |
| G | | | | | | | | | | |
| H | | | | | | | | | | |
As there are eight rows and ten columns, the total number of outcomes in the sample space is 8 x 10 = 80.
Next, we need to find the number of outcomes where the seat is in column 1.
Looking at the table, we can see that there is one seat in column 1 for each row. So, there are eight outcomes where the seat is in column 1.
Finally, we can calculate the probability by dividing the number of favorable outcomes (seats in column 1) by the total number of outcomes (total seats):
Probability = Number of favorable outcomes / Total number of outcomes
= 8 / 80
= 1 / 10
= 0.1
Therefore, the probability of selecting a seat at random that is in column 1 is 0.1 or 10%.
To create a table representing the sample space, we can list all the possible combinations of rows and columns.
Row | Column
------------
1 | 1
1 | 2
1 | 3
... | ...
8 | 9
8 | 10
In this case, since there are 8 rows and 10 columns, there are a total of 8 × 10 = 80 possible outcomes.
To find the probability of selecting a seat in column 1, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.
In this case, the number of favorable outcomes is 8 because there are 8 rows and we are only interested in column 1. The total number of possible outcomes is 80, as we calculated earlier.
Therefore, the probability of selecting a seat at random that is in column 1 is 8/80, which simplifies to 1/10 or 0.10.
In summary, the probability of selecting a seat at random in column 1 is 1/10 or 0.10.