thanks
Is sodium nitrate polar or nonpolar and how do I figure this out? thanks
You need to consult your text or your notes to see what you teacher calls ionic and what s/he calls covalent. Generally, a difference in electronegativity (you can look up the EN values for Na and for O or N) of 1.8 or so is called ionic and less than that is called covalent. But there is no sharp dividing line. For those in between we have polar covalent. I hope this helps.
.5-2 is polar covalent. i know there is a chart that says if sodium's electronegativity, but i can find no chart for nitrate
There is no chart for nitrate. You will need to look up N or O since the nitrate ion is NO3-
that doesn't make sense. how can you do just n or just o? aren't they connected?
If they are ionic, no. The salt will be present in water is the sodium ion with a +1 charge and the nitrate ion with a -1 charge. So whether it is ionic or not depends upon the electronegativity difference between Na and either N or O. In a sea of ions, it doesn't make all that much difference which you use. In addition, there is no sharp dividing line between what we consider ionic and what we consider covalent. Generally, most sodium salts are ionic. There are exceptions.
Hope this helps.
To determine whether sodium nitrate (NaNO3) is polar or nonpolar, we need to look at the electronegativity difference between the atoms involved. Electronegativity is a measure of an atom's ability to attract electrons in a chemical bond.
First, let's find the electronegativity values for sodium (Na), nitrogen (N), and oxygen (O). The electronegativity values can be found in a periodic table or by doing a simple web search.
Na: 0.93
N: 3.04
O: 3.44
Now, let's calculate the difference in electronegativity between sodium and nitrogen (ΔEN_na-n):
ΔEN_na-n = EN_n - EN_na = 3.04 - 0.93 = 2.11
Similarly, let's calculate the difference in electronegativity between sodium and oxygen (ΔEN_na-o):
ΔEN_na-o = EN_o - EN_na = 3.44 - 0.93 = 2.51
Based on the electronegativity differences, both the sodium-nitrogen bond and the sodium-oxygen bonds in sodium nitrate have values greater than 2, indicating a significant difference in electronegativity. This suggests that the sodium-nitrate molecule is more likely to be polar than nonpolar.
In conclusion, sodium nitrate (NaNO3) is likely to be a polar molecule due to the significant electronegativity difference between sodium and either nitrogen or oxygen.
To determine whether sodium nitrate is polar or nonpolar, you need to consider the electronegativity difference between the sodium atom and the nitrate ion. Sodium has an electronegativity value of around 0.93, while nitrogen and oxygen have values of around 3.04 and 3.44, respectively.
Based on the electronegativity difference, the bond between sodium and nitrate is considered ionic. Ionic bonds occur when there is a large electronegativity difference between the atoms involved. In the case of sodium nitrate, the large difference in electronegativity between sodium and nitrogen/oxygen indicates an ionic bond.
Therefore, sodium nitrate is considered polar because it forms ionic bonds.