# Chemistry

How can you balance Cu+HNo3=Cu+(No3)2+No+H2o by using algebric or a b c d method please show me with full workout

1. 👍
2. 👎
3. 👁
1. well I am not familiar with your methods but maybe
a Cu + b HNO3 = a Cu+c (NO3)2+ d NO + e H2O
a = a obviously, Cu only appears once and a can be any number at all
now H
b = 2 e
then N
b = 2 c + d
now O
3 b = 6 c + d + e
so now
use 2 e for b
2 e = 2 c + d
3(2e) = 6 c + d + e or 5 e = 6 c + d
so 3 e = 4 c
e = (4/3) c
then go back
if c = 3 to get an integer number for e
then e = 4
d = 2 e - 2 c = 8 - 6 = 2
and b = 2 e = 8
try it:
a Cu + 8 HNO3 = a Cu+ 3 (NO3)2+ 2 NO +4 H2O
any old a
8 H on each side
8 N on each side
24 O on each side
It works

I do not know why Cu, copper, is in your reaction since it does not react. Perhaps it is just to confuse you.

1. 👍
2. 👎
👤
Damon
Second. there is one BIG typo and several small ones. If you take care of the BIG one it takes care of Damon's problem AND you get the correct answer. Here is the corrected typo. I have removed the + sign between Cu and (NO3)2 on the product side. Now Damon doesn't have a problem because it shows Cu actually DID react. Now here is the correct equation using the caps key too.
Cu + HNO3 ==> Cu(NO3)2 + NO + H2O
Next you follow Damon's work and you end up with the balanced equation as follows:
3Cu + 8HNO3 ==> 3Cu(NO3)2 + 2NO + 4H2O

NOTE: This is a redox equation and I would NEVER use this method to balanced a reaction such as this one.
Another note: Note that this reaction is for Cu and DILUTE HNO3. The product is NO + the others.
When CONCENTRATED HNO3 is used the product is NO2 + others. That balanced equation is Cu + 4HNO3 ==> Cu(NO3)2 + 2NO2 + 2H2O.

1. 👍
2. 👎
👤
DrBob222

## Similar Questions

1. ### Chemistry

What is the ionic and net ionic equation for Na2CO3 + 2 HNO3 -> 2 NaNO3 + H2O + CO2 (g) This is what i have so far... Na2(aq)+CO3+H+NO3 -> Na+ NO3+ H2O(l)+CO2(g)... i don't know what to do!!!

2. ### chemistry

hi kinda stuck :) 100.0 ml of 0.100 M H2NNH2 (kb =3.0 x10^-6) is titrated by 0.200M calculate PH after adding the following volumes of HNO3 a 0 b 25.0 ml c 50.0 ml d 60.0 ml ----------------------------------------- A) N2H4 + HNO3

3. ### Chemistry

Write the ionic equation for these reaction. Ca(HCO3)2 + HCL = CaCl2 + CO2 + H2O ZnO + HNO3 = Zn(NO3)2 + H2O

4. ### chemistry

Which of the following are redox reactions? (a) Ba(NO3)2 (aq) + H2SO4 (aq) -> BaSO4 (s) + 2 HNO3 (aq) (b) NH4NO2 (s) -> N2 (g) + 2 H2O (g) (c) CuO (s) + H2 (g) -> Cu (s) + H2O (L)

1. ### chemistry

How do you balance this equation? Zn(s) + HNO3(aq)--> Zn(NO3)2(aq) + N2O(g) + H2O(l)

2. ### Chemistry

Hey, can you help me balance this equation? Cu2S + HNO3 --> Cu(NO3)2 + CuSO4 + NO2 +H2O Thanks!

3. ### Chem

In a 1.0x10^-6 M solution of HNO3(aq) at 25 degrees C, identify the relative molar amounts of species from most to least. HNO3 H3O+ H2O OH- NO3-

4. ### Chemistry

Balance the following redox equation by the oxidation number methode Ag + HNO3 = AgNO3 + NO + H2O I have all the oxidation numbers i just don't understand how i'm supposed to balance it according to them. I read the sites and i

1. ### Science

Balance this equation using oxidation method:I2+HNO3---->HIO3+NO2+H2O

2. ### Chemistry

NH3(g) + 2O2 (g) = HNO3 (aq) + H2O (l) How do I calculate the oxidation states of Nitrogen and figure out if it is reduced, oxidized or neither? My answer is below. I am not sure if I am figuring it right. Please advise. NH3(g) +

Question: Balance the following reactions by the oxidation number method. a) I2 + HNO3 --> HIO3 + NO2 + H2O so i have N +5 to +4 net charge = -1 I 0 to +5 net charge = +5 i add coefficient where the oxidation number is changing.

4. ### chem

For the reaction 3NO2 + H2O  2HNO3 + NO, how many grams of HNO3 can form when 1.00 g of NO2 and 2.25 g of H2O are allowed to react? This is a limiting reagent problem. 1. Write the equation. You have done that and it is balanced.