The length of a rectangle is 8 units longer that the width 2w. What is the perimeter of the rectangle?
well, if you define the width as 2w
then the length is 2w +8 (you said so)
so the perimeter would be 2 widths + 2 lengths
= 2(2w) + 2(2w+8)
= 4w + 4w + 16
= 8w + 16
why not just define the width as w instead of 2w ? Strange.
To find the perimeter of a rectangle, you need to add up the lengths of all four sides of the rectangle.
Let's start by defining the width of the rectangle as "w". The problem states that the length is 8 units longer than the width, which means the length can be represented as "2w + 8".
The formula for the perimeter of a rectangle is: P = 2(length + width)
Substituting the length and width values we obtained:
P = 2((2w + 8) + w)
Simplifying the equation:
P = 2(3w + 8)
P = 6w + 16
Therefore, the perimeter of the rectangle, in terms of "w", is 6w + 16.