A train leaves the station at time xequals
0.
Traveling at a constant speed, the train travels 328
km in 3.4
h. Round to the nearest 10 km and the nearest whole hour. Then represent the distance, y, the train travels in x hours using a table, an equation, and a graph.
To find the distance traveled by the train in x hours, we can use the given information that the train travels at a constant speed of 328 km in 3.4 hours.
Let's start by rounding the values to the nearest 10 km and the nearest whole hour.
Nearest 10 km: 330 km
Nearest whole hour: 3 hours
Now we can represent the distance, y, the train travels in x hours using a table, an equation, and a graph.
Table:
--------------
| x | y |
--------------
| 0 | 0 |
| 1 | 330 |
| 2 | 660 |
| 3 | 990 |
| 4 | 1320 |
------------
Equation:
The equation representing this scenario is y = 330x, where y represents the distance traveled in km and x represents the time in hours.
Graph:
On a graph, the x-axis represents time in hours, and the y-axis represents the distance traveled in km. The graph will be a straight line passing through the origin (0,0) with a slope of 330.
I hope this helps! Let me know if there's anything else I can assist you with.
To find the distance the train travels in x hours, we first need to determine the speed of the train.
Given:
Time (x) = 0
Distance travelled = 328 km
Time taken = 3.4 hours
To find the speed, we can divide the distance by the time taken:
Speed = Distance / Time taken
Speed = 328 km / 3.4 hours
Speed ≈ 96.47 km/h (rounded to two decimal places)
Now, let's create a table to represent the distance, y, the train travels in x hours.
Table:
| x (hours) | y (distance traveled in km) |
|-----------|----------------------------|
| 0 | 0 |
| 1 | 96 |
| 2 | 192 |
| 3 | 289 |
| 4 | 385 |
| 5 | 481 |
| 6 | 577 |
| 7 | 673 |
To express this relationship in an equation, we can use the equation for distance:
y = Speed * x
Where:
y = distance in km
Speed = 96.47 km/h (rounded to two decimal places)
x = time in hours
Graphically, the relationship between x and y can be represented as a straight line with a slope of 96.47 and passing through the origin (0, 0).
Note: The y-values in the table above are rounded to the nearest whole number.
speed = 328km/3.4hr = 96.47 km/hr
If we round before calculating, that is 330/3 = 110 km/hr
x y
0 0
10 1100
20 2200
...
Or maybe you want to round after calculating. You're kinda vague.