A 0.02 kg bullet has a speed of 500 m/sec. What is its kinetic energy
(1/2) m v^2 = (1/2)(0.02)(500)(500) Joules = 5 * 500 = 2500 Joules
To calculate the kinetic energy of the bullet, you can use the formula:
Kinetic Energy = 1/2 * mass * velocity^2
Given:
Mass (m) = 0.02 kg
Speed (v) = 500 m/sec
Plugging in the values into the formula, we have:
Kinetic Energy = 1/2 * 0.02 kg * (500 m/sec)^2
Now, let's calculate step-by-step:
Step 1:
Squaring the speed: (500 m/sec)^2 = 250,000 m^2/sec^2
Step 2:
Multiplying the squared speed by the mass: 0.02 kg * 250,000 m^2/sec^2 = 5,000 kg * m^2/sec^2
Step 3:
Multiplying by 1/2: 5,000 kg * m^2/sec^2 * 1/2 = 2,500 kg * m^2/sec^2
Therefore, the kinetic energy of the bullet is 2,500 kg * m^2/sec^2.
To find the kinetic energy of an object, you can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
In this case, the mass of the bullet is given as 0.02 kg and the velocity is 500 m/sec.
Substituting these values into the formula:
Kinetic Energy = (1/2) * 0.02 kg * (500 m/sec)^2
Now let's solve the equation step by step:
Step 1: Calculate the square of the velocity
(500 m/sec)^2 = 250,000 m^2/sec^2
Step 2: Multiply the square of the velocity by the mass
0.02 kg * 250,000 m^2/sec^2 = 5,000 kg⋅m^2/sec^2
Therefore, the kinetic energy of the bullet is 5,000 kg⋅m^2/sec^2.