ahamd and manu works in sweet shop during eid ahmad and manu charges . 200 and 250 a day respectively, to work in the kitchen. their combined earning during the eid period was rs 3900. if in total manu earned rs 1100 more than ahmad. how many day did each one work for? what payement did each one recieve?
3,900 - 1,100 = 2,800
2,800 / 2 = 1,400
1,400 + 1,100 = 2,500
Ahmad = 1,400
Manu = 2,500
1,400 / 200 = 7
2,500 / 250 = 10
Ahmad worked for 7 days
Manu worked for 10 days
A+M=3900
M-1100=A or
M-1100+M=3900 solve for M first.
Let's solve this step-by-step.
Step 1: Let's assume the number of days Ahmad worked as 'x'.
Step 2: Since Manu earned Rs 1100 more than Ahmad, we can calculate Manu's earnings as (x + 1100).
Step 3: Ahmad earns Rs 200 per day, so his total earnings will be 200x.
Step 4: Manu earns Rs 250 per day, so his total earnings will be 250(x + 1100).
Step 5: The combined earnings of Ahmad and Manu during the Eid period is given as Rs 3900.
Step 6: Write an equation for the combined earnings: 200x + 250(x + 1100) = 3900.
Step 7: Solve the equation for x.
200x + 250x + 275000 = 3900
450x + 275000 = 3900
450x = 3900 - 275000
450x = -271100
x = -271100/450
x = -602.44
Since we can't have a fraction of a day, the value of x doesn't make sense in this context. Please double-check the given information to ensure it is accurate.
To solve this problem, let's assume that Ahmad worked for x days and Manu worked for y days.
According to the problem, Ahmad charges Rs 200 per day and Manu charges Rs 250 per day. So, the earnings of Ahmad and Manu can be calculated as follows:
Earnings of Ahmad = 200 * x
Earnings of Manu = 250 * y
The problem states that their combined earnings during the Eid period were Rs 3900. Therefore, we can write the following equation:
200 * x + 250 * y = 3900 -- (Equation 1)
The problem also states that Manu earned Rs 1100 more than Ahmad. So, we can write another equation:
250 * y = 200 * x + 1100 -- (Equation 2)
Now, we can solve these two equations to find the values of x and y, which represent the number of days each person worked.
To simplify Equation 1, let's divide it by 50 to get:
4x + 5y = 78 -- (Equation 3)
Now, we can substitute the value of (200 * x + 1100) from Equation 2 into Equation 3:
4x + 5y = 200x + 1100
Rearranging this equation, we get:
200x - 4x = 5y - 1100
196x = 5y - 1100
Since we know that x and y are integers, let's examine the various values of y to find a suitable pair that satisfies this equation.
Let's start with y = 0:
196x = 5(0) - 1100
196x = -1100
This is not possible if x is an integer.
Next, let's try y = 1:
196x = 5(1) - 1100
196x = -1095
This is not possible either.
Now, let's try y = 2:
196x = 5(2) - 1100
196x = -1090
Still not possible.
Let's keep trying different values of y:
y = 3: 196x = 5(3) - 1100
196x = -1085
y = 4: 196x = 5(4) - 1100
196x = -1080
y = 5: 196x = 5(5) - 1100
196x = -1075
Finally, when y = 6, we get:
196x = 5(6) - 1100
196x = -1070
This equation is solvable if x is an integer. By dividing both sides of the equation by 196, we find:
x = -1070 / 196
x ≈ -5.449
Since x represents the number of days, we cannot have a negative number of days. Therefore, it means that our assumption about the value of y = 6 is incorrect.
In conclusion, there is no integer solution to this problem, which means it is not possible to find the exact number of days each person worked and the exact payments they received.