How would the kinetic energy of a 12,000-kg train compare with the kinetic energy of a 900-kg compact car of both were traveling at the same speed?

I am rlly not good at this im still confused!

To compare the kinetic energy of the train and the compact car, we first need to understand the formula for kinetic energy:

Kinetic Energy = 1/2 * mass * velocity^2

In this case, the mass of the train is given as 12,000 kg, and the mass of the compact car is given as 900 kg. Assuming they are both traveling at the same speed, let's use "v" to represent their velocity.

Now, to compare their kinetic energies, we need to calculate the kinetic energy for each object using the formula mentioned above.

1. Train:
Kinetic Energy (train) = 1/2 * mass (train) * velocity^2
= 1/2 * 12,000 kg * v^2

2. Compact Car:
Kinetic Energy (car) = 1/2 * mass (car) * velocity^2
= 1/2 * 900 kg * v^2

So, the kinetic energy of the train would be 1/2 * 12,000 kg * v^2, and the kinetic energy of the compact car would be 1/2 * 900 kg * v^2.

To directly compare their kinetic energies, we need to find the ratio of the kinetic energy of the train to the kinetic energy of the compact car:

Ratio = (Kinetic Energy of Train) / (Kinetic Energy of Car)
= (1/2 * 12,000 kg * v^2) / (1/2 * 900 kg * v^2)

Simplifying the equation:

Ratio = (12,000 kg / 900 kg) = 13.33

Based on this comparison, the kinetic energy of the train is 13.33 times greater than the kinetic energy of the compact car when they are traveling at the same speed.

is this homework help or not

the K.E. is proportional to the mass

the mass of the train is about 13 times the mass of the car
... so it has about 13 times the K.E.