"A student mixed two clear liquids together in a beaker. A solid and new liquid formed. The student forgot to write down the mass of one of the reactants. The rest of the data is shown in the table below."
The data (mass, in grams):
Liquid reactant A: unknown
Liquid reactant B: 9.0
Liquid product: 8.0
Solid product: 12.0
I don't want to know if it's A, B, C, or D because I already know the answer. If someone could please explain how to find liquid reactant A's mass I would appreciate that greatly, because I need to know how to do this on my own. Thank you in advance
NEVERMIND! I'm dumb! I just had to add the liquid and solid product and subtract them from 9 to get 11.
Good job to figure it out on your own!
Congrats!!
Yes, mass is conserved :)
To find the mass of liquid reactant A, we can use the principle of conservation of mass. According to this principle, the total mass of reactants must be equal to the total mass of products.
In this case, we know the mass of reactant B, which is 9.0 grams. We also know the mass of the liquid product, which is 8.0 grams, and the mass of the solid product, which is 12.0 grams.
To calculate the mass of reactant A, we can subtract the total mass of the products (liquid product + solid product) from the total mass of the reactants (liquid reactant A + liquid reactant B):
Total mass of reactants = Total mass of products
Mass of reactant A + Mass of reactant B = Mass of liquid product + Mass of solid product
Now, we can rearrange the equation to solve for the mass of reactant A:
Mass of reactant A = Mass of liquid product + Mass of solid product - Mass of reactant B
Substituting the given values into the equation:
Mass of reactant A = 8.0 grams + 12.0 grams - 9.0 grams
Simplifying the equation:
Mass of reactant A = 11.0 grams
Therefore, the mass of liquid reactant A is 11.0 grams.