The perimeter of a soccer field is 340m. The length exceeds width by 50m. Find the Length and Width.

2 L + 2 W = 340 ... L + W = 170

L = W+ 50

solve the system for L and W

Thank you.

Width = W.

Length = W+50.
2W + 2(W+50) = 340,
W = 60 cm. = width.
W+50 = 110 cm = Length.

Why did the soccer field go on a diet? Because it wanted to reduce its perimeter!

Let's solve this puzzle. We are given that the perimeter of the soccer field is 340m.

Let's call the width of the field "x" (in meters). According to the problem, the length exceeds the width by 50m, so we can say the length is (x+50).

The perimeter of a rectangle is given by the formula:
Perimeter = 2(length + width).

Using this formula, we can write the equation as:
340 = 2[(x+50) + x].

Let's now solve this equation:

340 = 2(2x + 50).
340 = 4x + 100.
240 = 4x.
x = 60.

Therefore, the width of the soccer field is 60m, and the length is 60 + 50 = 110m.

So, the length of the soccer field is 110m and the width is 60m. Keep those kickin' soccer balls!

To find the length and width of the soccer field, we can set up a system of equations based on the given information.

Let's denote the length of the soccer field as "L" and the width as "W".

We're told that the perimeter of the soccer field is 340m. The perimeter of a rectangular shape is calculated as P = 2L + 2W. Therefore, in this case, we have:

2L + 2W = 340 ...(Equation 1)

We're also given that the length exceeds the width by 50m, which can be expressed as:

L = W + 50 ...(Equation 2)

Now, we can solve this system of equations to find the length and width.

First, let's substitute the value of L from Equation 2 into Equation 1:

2(W + 50) + 2W = 340

Now, simplify the equation:

2W + 100 + 2W = 340
4W + 100 = 340

Next, isolate the variable:

4W = 340 - 100
4W = 240

Finally, solve for W:

W = 240 / 4
W = 60

Now, substitute the value of W back into Equation 2 to find L:

L = 60 + 50
L = 110

Therefore, the length of the soccer field is 110m and the width is 60m.