Physics

A capacitor is constructed with two parallel metal plates each with an area of 0.61 m^2 and separated by d = 0.80 cm. The two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each of the oppositely charged plates. Find the charge Q.

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  1. I'm stuck, please help
    the second question the above question is Find the capacitance of the parallel plates.

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  2. I have to use this formula to find Q Q = CΔV, and C = (ε0*A)/d

    These are what I did but don't know what ε0 is
    C= (ε0*0.61 m^2 )/.0080m= stuck here. Is there anybody know what to do from here?

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  3. ε0=8.85*10^-12
    C=[(8.85*10^-12)*.61]/.008=
    Q=([(8.85*10^-12)*.61]/.008=)*5=
    Parallel Plate Capacitor Capacitance Calculator for second question
    www.daycounter.com/Calculators/Plate-Capacitor-Calculator.phtml

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