# chemistry

What mass of lead (ii)trioxonitrate(v)pb (No3)2 would be required to yield 25g of pbcl on the addition of excess of Nacl solution (Pb=207,N=14,O=16,Na=23,Cl=35.5)

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Pb(NO3)2 + 2NaCl → PbCl + 2NaNO3
then each mole of Pb(NO3)2 yields one mole of PbCl.
So, how many moles of PbCl do you have in 25 grams?
convert that to grams of Pb(NO3)2

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posted by oobleck
2. You need to start over. Lead(II) chloride is PbCl2. Enough said?
And lead (II) trioxonitrate(V) is not an IUPAC approved name for lead(II) nitrate

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