MgCl2(s) → Mg2+(aq) + 2Cl^-(aq)
How many total ions?
2.0 x 10^5 N2O3
How many total atoms?
How many nitrogen atoms and oxygen atoms?
1 Mg ion and 2 chloride ions in 1 molecule of MgCl2.
2E5 what?
To find the total number of ions in a chemical equation or reaction, you need to analyze the coefficients of the reactants and products that undergo ionization or dissociation in a solution.
In the case of the reaction:
MgCl2(s) → Mg2+(aq) + 2Cl^-(aq)
We can determine the total number of ions by examining the coefficients of the dissociated species (ions).
From the reaction equation, we see that MgCl2 dissociates into one Mg2+ ion and two Cl- ions. So, there are a total of 3 ions (1 Mg2+ and 2 Cl- ions) formed in this reaction.
To calculate the total number of atoms in a given quantity of a substance, we need to analyze the subscript numbers in the chemical formula and multiply them by the corresponding coefficient.
For example, if we have 2.0 x 10^5 N2O3, we can determine the total number of atoms as follows:
N2O3 can be broken down into 2 nitrogen (N) atoms and 3 oxygen (O) atoms. Therefore, to find the total number of atoms, we need to multiply the respective subscripts by the coefficient.
Total number of nitrogen atoms: 2 (subscript) * 2.0 x 10^5 (coefficient) = 4.0 x 10^5 nitrogen atoms
Total number of oxygen atoms: 3 (subscript) * 2.0 x 10^5 (coefficient) = 6.0 x 10^5 oxygen atoms
So, there are 4.0 x 10^5 nitrogen atoms and 6.0 x 10^5 oxygen atoms in 2.0 x 10^5 N2O3.