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Algebra  sqrts
Square roots. Woohoo. Want to check some work I did. 1. Perform indicated operations 3sqrt[3]+2sqrt[27]sqrt[12] 3sqrt[3]+2sqrt[3*9]sqrt[2*6] 3sqrt[3]+3*2sqrt[3]2sqrt[3] 3sqrt+6sqrt[3]2sqrt[3] = 7sqrt[3] 2.Simplify
asked by John on November 6, 2007 
math,correction from previous post
can someone please correct this for me thanks. simplify: 7sqrt(7x) + 5 sqrt (7x) My work: (7+5)sqrt (7x) My answer: 12sqrt (7x) is this correct? yup so i don't have to take out the x from the radicand Nope. 7x + 5x = 12x No matter
asked by jasmine20 on April 19, 2007 
Algebra
Square roots. Woohoo. Want to check some work I did. 1. Perform indicated operations 3sqrt[3]+2sqrt[27]sqrt[12] 3sqrt[3]+2sqrt[3*9]sqrt[2*6] 3sqrt[3]+3*2sqrt[3]2sqrt[3] 3sqrt+6sqrt[3]2sqrt[3] = 7sqrt[3] 2.Simplify
asked by John on November 6, 2007 
algebra,math,help
Use Property 2 to simplify each of the following radical expressions. sqrt (10)/ sqrt(49) My answer: sqrt (10) / (7) THis next one i need help: Use the properties for radicals to simplify each of the following expressions. Assume
asked by jas20 on March 9, 2007 
algebra
am I right? 1. Simplify radical expression sqrt 50 5 sqrt ^2*** 2 sqrt ^5 5 sqrt ^10 5 2. Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqrt
asked by Carl Wheezer on May 7, 2017 
math
how would you simplify this equation: y = (x+3)/[(4sqrt(16+h))] please help me! you have three variables. I am not certain "simplify" is an appropriate term here. ohhhh it was my mistake. I meant: y = h/[(4sqrt(16+h))] y =
asked by kristie on June 30, 2006 
math,algebra,help
Directions are simplify by combining like terms. x radiacal 18 3 radical 8x^2 can someone show me how to do these types of problems. thanks I cant determine the second term. For the first, I think you meant x sqrt(18) which
asked by Jasmine20 on January 26, 2007 
Inequality
When I solve the inquality 2x^2  6 < 0, I get x < + or  sqrt(3) So how do I write the solution? Is it (+sqrt(3),sqrt(3)) or (infinity, sqrt(3))? Why? Thanks. So would this work? abs x < ( sqrt 3 ) or  sqrt 3
asked by Jen on November 5, 2006 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2,
asked by COFFEE on July 10, 2007 
Algebra
Evaluate sqrt7x (sqrt x7 sqrt7) Show your work. sqrt(7)*sqrt(x)sqrt(7)*7*sqrt(7) sqrt(7*x)7*sqrt(7*7) sqrt(7x)7*sqrt(7^2) x*sqrt 7x49*x ^^^ would this be my final answer?
asked by Alexa on February 17, 2016