When lifting an object vertically, would either Fn or Fg be longer on a free body diagram? Explain.

It depends. Net force = mass * acceleration

force down = m g = Fg
force up = Fn (I suppose although you did not say)
Fn - Fg = m a
if the acceleration, a is up, Fn is bigger
if the acceleration, a is down, Fg is bigger

When lifting an object vertically, the free body diagram of the object would include a force due to gravity (Fg) acting downward. This force represents the weight of the object and is always constant for a given object. Thus, the length of the arrow representing Fg on the free body diagram would be fixed and not change during the lifting process.

On the other hand, the other force involved in lifting the object is the normal force (Fn) exerted by the person or the lifting device. The normal force is the force exerted by a surface to support the weight of an object resting on it. In the case of lifting an object vertically, the person or the lifting device has to exert a force greater than the weight of the object in order to overcome gravity and lift it.

Therefore, the magnitude of the normal force (Fn) would be longer than the magnitude of the force due to gravity (Fg) on the free body diagram when lifting an object vertically.

To determine whether the normal force (Fn) or the force due to gravity (Fg) would be longer on a free body diagram when lifting an object vertically, we need to consider the forces involved.

The force due to gravity (Fg) is the gravitational pull acting on an object and is given by the formula Fg = m * g, where m is the mass of the object and g is the acceleration due to gravity.

The normal force (Fn) is the force exerted by a surface perpendicular to the object's contact point. In this case, when lifting an object vertically, the object's contact point will be with your hand or the lifting device.

When an object is at rest or moving at a constant velocity, the net force acting on it is zero. This means that the force you apply upwards to lift the object should be equal in magnitude but opposite in direction to the forces acting downwards (such as gravity).

So, when you lift an object vertically, the force you apply (upward force) would need to be equal in magnitude but opposite in direction to the force due to gravity (downward force). Therefore, the normal force (Fn) would be longer on a free body diagram.

To summarize: When lifting an object vertically, the normal force (Fn) would be longer on a free body diagram compared to the force due to gravity (Fg).