math,correction
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math,correction
is this correct: solve by using the quadratic formula 5x^2+x=3 what i keep getting is this: (1 +/ sqrt 61)/(10) or should i reduce the denominator to 5 or is my whole answer incorrect? (1 +/ sqrt 61)/(10) looks correct. You do
asked by jasmine20 on April 19, 2007 
AlgebraPlease check
1. solve sqrt (11x) = sqrt(x7) choices are 6,7,8 or9 I think according to my calcs the answer is (9) The range of f(x) = sqrt(3x6)  2 answers would be y= (2) y> (2) y
asked by Erica on January 8, 2011 
some algebra help (radicals)
I hope I am writing this down right.. I am trying to do some practice questions to learn 10^5 (sqrt)2y  4^5 (sqrt)2y I am trying to figure out how to solve this They gave us some answers to choose from, but I am clueless on how
asked by Cassie on May 6, 2007 
Inequality
When I solve the inquality 2x^2  6 < 0, I get x < + or  sqrt(3) So how do I write the solution? Is it (+sqrt(3),sqrt(3)) or (infinity, sqrt(3))? Why? Thanks. So would this work? abs x < ( sqrt 3 ) or  sqrt 3
asked by Jen on November 5, 2006 
math,correction
i am really trying is this correct. solve: 5(x2)^2 = 3 MY ANSWER THAT I GOT IS: X = 2 + (SQRT (3) )/(5) no. 5(x2)^2 = 3 (x2)^2 = 3/5 x2 = + sqrt (3/5) x= 2 + sqrt (3/5) so the whole fraction of 3/5 is inside the sqrt yes
asked by jasmine20 on April 15, 2007 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2,
asked by COFFEE on July 10, 2007 
ALGEBRA 1
Solve the following I am not sure if I did this correct (n5)^2= 20 n5=+/ 20 n=5+/ sqrt 20 Thanks yes on the final answer. On the second line, you forgot to type sqrt before 20. You can reduce it some....sqrt20= sqrt(4*5)= 2
asked by DANIELLE on April 18, 2007 
Math Help please!!
Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine
asked by Reggie on May 20, 2007 
Algebra
Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solve for s: h=(square root of 3)times s/2 Multiply both sides by 2. 2h = (sqrt 3)*s*2/2 which cancels the 2 on the right. 2h = (sqrt 3)*s Now
asked by Jamie on August 17, 2006 
Math
So I am supposed to solve this without using a calculator: Sqrt[20]/10  Sqrt[10]/Sqrt[32]  Sqrt[0.3125] + Sqrt[3 + 1/5] You can put this into WolframAlpha as is to make it prettier. Answer given is 1/2 * SQRT(5) I really don't
asked by Mr.AMG on April 17, 2015