Calculate the number of atoms of chlorine present in 7.45g of KCL
No of atoms present in 7.45g KCL
I don't know what to write in my Home-work which says :what is the number of atoms of chlorine present in 7.45g of potassiumchloride.
Thanks bye 🤓
Well, let's start by figuring out the molar mass of KCl.
The molar mass of K is approximately 39.1 g/mol, and the molar mass of Cl is approximately 35.45 g/mol.
Now, we need to find the number of moles of KCl in 7.45g. We can do this by dividing the mass (in grams) by the molar mass (in grams per mole).
So, the number of moles of KCl is:
7.45g / (39.1 g/mol + 35.45 g/mol) = 7.45g / 74.55 g/mol
Now, since KCl has a 1:1 ratio of K to Cl, the number of moles of Cl in 7.45g of KCl is the same as the number of moles of KCl.
Therefore, the number of atoms of Cl in 7.45g of KCl can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 atoms in one mole.
So, the number of atoms of Cl in 7.45g of KCl is approximately:
(7.45g / 74.55 g/mol) x (6.022 x 10^23 atoms/mol)
But hey, let's not forget that we're dealing with Clowns here! So, instead of giving you a serious answer, I'll throw you a joke:
Why did the scarecrow become a chemist?
Because he wanted to get his Bunsen burner!
To calculate the number of atoms of chlorine present in 7.45g of KCl, you need to follow these steps:
1. Determine the molar mass of KCl:
- The molar mass of potassium (K) is 39.10 g/mol.
- The molar mass of chlorine (Cl) is 35.45 g/mol.
- The molar mass of KCl is the sum of the molar masses of potassium and chlorine: 39.10 + 35.45 = 74.55 g/mol.
2. Use the molar mass to convert grams to moles:
- Divide the given mass of KCl (7.45g) by the molar mass (74.55 g/mol) to obtain the number of moles of KCl: 7.45 g / 74.55 g/mol = 0.10 mol.
3. Use the stoichiometry of the compound to determine the number of moles of chlorine:
- In KCl, each formula unit contains one chlorine atom.
- Therefore, the number of moles of chlorine is also 0.10 mol.
4. Convert moles to atoms using Avogadro's number:
- Avogadro's number is 6.022 x 10^23 atoms/mol.
- Multiply the number of moles of chlorine by Avogadro's number to get the number of atoms of chlorine: 0.10 mol * 6.022 x 10^23 atoms/mol = 6.022 x 10^22 atoms of chlorine.
Therefore, there are approximately 6.022 x 10^22 atoms of chlorine present in 7.45g of KCl.
number moles KCl= 7.45/(74.6)= ...
Number atome chlorine= numbermolesKCl * 6.02*10^23