# Algebra

A science teacher has a supply of 20% saline solution and a supply of 50% saline solution. How much of each solution should the teacher mix together to get 60 mL of 28% saline solution for an experiment?

I have an idea of what to do but need some help.

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1. let the amount of the 20% stuff be x ml
then the amount of the 50% stuff is 60-x ml

solve for x
.20x + .50(50-x) = .28(60)
20x + 50(60-x) = 28(60)
continue

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👨‍🏫
Reiny

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