Find two consecutive odd integers such that their product is 31 more than 2 times their sum?
I GOT THE FIRST PART OF IT BUT I DONT KNOW HOW TO GET THE SECOND
To find two consecutive odd integers, let's represent the first odd integer as 'x'. Since the next odd integer will be consecutive to 'x', we can represent it as 'x + 2' (as every odd integer can be represented as '2n + 1', where 'n' is an integer).
Now we can form the equation using the information given. The product of these two consecutive odd integers is (x)(x + 2), and their sum is (x) + (x + 2). According to the problem, the product should be 31 more than twice their sum. So we have the equation:
(x)(x + 2) = 2[(x) + (x + 2)] + 31
Now we can solve this equation to find the value of 'x', which will give us the two consecutive odd integers.