Find two consecutive odd integers such that their product is 39 more than 9 times their sum?

so, using the previous suggestion,

x(x+2) = 39 + 9(x + x+2)
Now just finish it off ...

HELP HAS TO BE DONE BY 12

Let the two odd consecutive numbers be x and x+2

x(x+2) - 9(x + x+2) = 39

x^2 + 2x - 18x - 18 = 39
x^2 - 16x - 57 = 0
(x -19)(x + 3) = 0
x = 19 or x = -3

the two consecutive odds are either 19 and 21 OR -3 and -1

check 19,21
product = 399
9 times their sum = 9(40) = 360
yes, their product is 39 more than 9 times their sum

check -3, -1
their product is 3
9 times their sum is 9(-4) = -36
and 3 is greater than -36 by 39

so both of my answers are correct

to the suggestion above. When I Solve it I get -3,19 but its saying its wrong

You are not getting the right conclusion

the value of x is indeed -3 and 19

but I called the two numbers x and x+2

so if you use x = 19, your two consecutive odds are 19 and 21
if you use x = -3, you would have -3 and -1

I verified both answers, did you not read my solution???

To solve this problem, let's start by assuming the first odd integer is represented by the variable "x." Since we are looking for consecutive odd integers, the second integer would be "x + 2" since it will be two more than the first odd integer.

According to the problem, the product of these two consecutive odd integers is 39 more than 9 times their sum. Mathematically, this can be represented as:

x * (x + 2) = 9 * (x + (x + 2)) + 39

Now, let's simplify this equation step by step:

x * (x + 2) = 9 * (2x + 2) + 39 (distributing 9 to the sum inside parentheses)

x^2 + 2x = 18x + 18 + 39 (expanding both sides of the equation)

x^2 + 2x - 18x - 57 = 0 (combining like terms)

x^2 - 16x - 57 = 0 (simplifying)

Now, we have a quadratic equation that can be solved by factoring, completing the square, or using the quadratic formula. To keep this explanation simple, let's solve it by factoring:

(x - 19)(x + 3) = 0

Setting each factor equal to zero:

x - 19 = 0 or x + 3 = 0

Solving for x in each case:

x = 19 or x = -3

So, we have two potential values for x: 19 and -3. Since we are looking for odd integers, we can discard the negative value. Therefore, the first odd integer, represented by x, is 19.

The second odd integer, x + 2, can be calculated as:

19 + 2 = 21

Therefore, the two consecutive odd integers that satisfy the given condition are 19 and 21.

solve for x and a tutor will check your work.

I already gave you a hint the last time you posted this question.