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Create a detailed image of a laboratory setting. There are various scientific apparatus spread around, including beakers, flasks, and glass tubing. In the center of the image, there's a well-lit, transparent container filled with a pale crystal-like substance, signifying AL2(SO4)3, with symbols for aluminium and sulphur, embodying the process of calculating the oxidation number. Please keep the image rich in color but without any written text.

Calculate the oxidation number of sulphur in AL2(SO4)3

Al2(SO4)3

2Al+3S+12O=0
2(+3)+3S+12(-2)=0
6+3S-24=0
3S=0-6+24
3S=18
3S/3=18/3
S=+6

2(3)+3x+(-2)12=0

6+3x-24=0
3x-18=0
3x=18
x=6

I want aluminum

al2(so4)3 oxidation number

Al=+3 based on the periodic group rule...

S=+6
O=-2

al2 (so4) 3 = ?

Al2(SO4)3

Oxdn no: of Oxygen is -2
3×2+3×x+3×4×(-2)=0
6+3x-24=0
3x-18=0
3x=18
∴x=+6

Al2(SO4)3

2(O.N.of Al)+3[(O.N.of S)+4(O.N.of O)]=0
2(+3)+3(O.N.of S)+12(-2)=0
6+3(O.N.of S)-24=0
3(O.N.of S)=24-6
3(O.N.of S)=18
O.N.of S=18/3
O.N.of S=+6

3(2)+3×+12(-2)=0

6+3×-24=0
3×-18=0
3×/3=18/3
×=+6

S is +6. That last line Damon is showing that it checks out for S = +6 combined with -8 for the 4 O atoms leaves -2 for the SO4 ion as it should be.