If 500 g of KClO3 decomposes and produces 303 g of KCl, how many grams of O2 are produced?
To determine the number of grams of O2 produced, we first need to find the mass of oxygen within KClO3, and then use stoichiometry to calculate the mass of O2.
The given information tells us that 500 g of KClO3 decomposes and produces 303 g of KCl. Since the KClO3 decomposes into KCl and O2, the total mass of KClO3 is divided into the sum of the masses of KCl and O2. We can calculate the mass of O2 using the following equation:
Mass of O2 = Mass of KClO3 - Mass of KCl
Mass of O2 = 500 g - 303 g
Mass of O2 = 197 g
Therefore, 197 grams of O2 are produced during this reaction.
First step: what is the balanced equation for the reaction?
Change 303g to moles.
The equation will tell you how many moles of O2 there are for each mole of KCl.
Convert that back to grams.