a ball tossed to a height of 4 meters rebounds 40% of its previous height. the total distance travelled by the ball by the time it comes to rest is?
distance
= 2(4 + 4(.4) + 4(.4)^2 + ....
= 2(sum of infinite GS) and using S∞ = a/(1-r)
= 2(4/(1-.4) ) = 40/3 metres
When a ball is tossed to a height of 4 meters above the ground i t always rebound to 40% of its previous height until it stop .Ring the total distance that the ball has covered when it strikes the ground for the fifth time
A ball tossed to a height of 4 meters rebounds to 40% of its previous height.Find the distance the ball has traveled when it strikes the ground for the fifth time
a1 = 8 r =3.2/ 8 n= 5
Sn= a1(1-rn)/ 1-r → S5= 8(1-0.4^5)/1-0.4 = 13.1968m = 13.2 meters
3.2
a1= 4
r= 40% or 0.40
S5=?
◾Sn=a1(1-r^n) / 1-r
◾s5= 4(1-0.40^5) / 1-0.40
◾s5= 4(0.98976) / 0.60
◾s5= 6.5984 or 6.60 meters