Sodium carbonate can be made to react with carbon in the presence of nitrogen gas to produce sodium cyanide and carbon monoxide. How many moles of carbon are in the balanced equation?
Can someone help me write the equation. My answer was 10 moles of C but it's wrong. Any help is much appreciated
about 10 seconds with google produced the equation
Na2CO3 + N2 + 4C = 2NaCN + 3CO
So then what is the answer because i got 10 but it is wrong and I'm so confused as to why
Sure, I'd be happy to help you out! Let's start by writing out the balanced equation for this reaction:
Na2CO3 + C + N2 -> 2 NaCN + CO
Now, let's take a look at the coefficients in front of each compound. In this equation, we can see that there is only one carbon atom involved, and it has a coefficient of 1. So, there is only 1 mole of carbon in the balanced equation.
Therefore, the correct answer is 1 mole of carbon, not 10 moles of carbon. Keep in mind that the coefficients in a balanced equation represent the ratio of moles, not the actual number of moles.
I apologize if my explanation didn't make you laugh, but I hope it helped you understand the correct answer! If you have any more questions, feel free to ask.
To write the balanced equation for the reaction given, let's first determine the chemical formulas of the reactants and products involved.
Reactants:
- Sodium carbonate: Na2CO3
- Carbon: C
- Nitrogen gas: N2
Products:
- Sodium cyanide: NaCN
- Carbon monoxide: CO
The balanced equation can be written as follows:
Na2CO3 + 2C + N2 → 2NaCN + CO
Now, let's count the number of moles of carbon in the balanced equation. From the equation, we can see that there are two moles of carbon (2C) on the reactant side.
Therefore, there are 2 moles of carbon in the balanced equation, not 10 moles.
To write the balanced equation for the reaction between sodium carbonate, carbon, and nitrogen gas, we need to consider the stoichiometry of the reaction.
The balanced equation is as follows:
2 Na2CO3 + 5 C + 2 N2 -> 4 NaCN + 5 CO2
To determine the number of moles of carbon in this equation, we look at the stoichiometric coefficient in front of C, which is 5. This means that in the balanced equation, 5 moles of carbon react with 2 moles of sodium carbonate.
Therefore, the correct answer is that there are 5 moles of carbon in the balanced equation, not 10 moles as you initially thought.
Remember to always pay attention to the balanced equation and its stoichiometric coefficients to determine the correct number of moles of each substance involved in the reaction.