math

(dy/dx)=X^3/8 - 1/2x^3.
what is sqrt( 1+(dy/dx)^2 ) and that multiplied by (dy/dx)

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  1. It is sqrt(dy/dx^2 + dy/dx^4)

    Is your first dy/dx term x^(3/8) or (x^3)/8 ? Is the second term (1/2)x^2 or 1/(2x^3) ?

    It seems to me all you have to do is substitute the dy/dx you already know into whatever you want to calculate.

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