Given the following equation: ____ K + ____Cl2 --> ____ KCl
How many grams of KCl is produced from 2.50 g of K and excess Cl2?
1. balance the equation
2. for every atom of K, how many molecules of KCl do you get?
3. how much is a gram mole mass of K?
4. How much is a gram mole mass of Cl,
5. add 3. to 4. to get gram mole mass of KCl
6. 2.5 * result of 5/result of 3
To solve this problem, we need to find the balanced equation first. Since the equation is not provided, we will balance it.
Let's assume the balanced equation is:
2K + Cl2 -> 2KCl
From the balanced equation, we can see that 2 moles of K react with 1 mole of Cl2 to produce 2 moles of KCl.
Now, let's calculate the number of moles of KCl produced from 2.50 g of K.
First, we need to convert the mass of K to moles using its molar mass.
The molar mass of K is 39.10 g/mol.
Number of moles of K = mass / molar mass
Number of moles of K = 2.50 g / 39.10 g/mol ≈ 0.064 moles
Since 2 moles of K reacts to produce 2 moles of KCl, we can say that 0.064 moles of K will produce 0.064 moles of KCl.
Finally, we can calculate the mass of KCl produced using its molar mass:
The molar mass of KCl is 74.55 g/mol.
Mass of KCl = moles of KCl * molar mass
Mass of KCl = 0.064 moles * 74.55 g/mol ≈ 4.77 g
Therefore, approximately 4.77 grams of KCl is produced from 2.50 grams of K.
To find out how many grams of KCl are produced from 2.50 g of K, we need to determine the stoichiometric ratio between K and KCl in the balanced chemical equation.
Let's start by balancing the equation:
____ K + ____ Cl2 --> ____ KCl
Counting the number of K atoms on both sides of the equation, we see that there is one potassium atom on the left side and one on the right side after balancing the equation. Therefore, the coefficient for K is 1.
____ K + ____ Cl2 --> 1 KCl
Now, let's find the stoichiometric ratio between K and KCl by comparing the coefficients:
1 mol K = 1 mol KCl
The molar mass of K (potassium) is 39.10 g/mol. Therefore, 39.10 g of K corresponds to 39.10 g of KCl.
To determine the mass of KCl produced from 2.50 g of K, we can use a simple ratio:
2.50 g K × (39.10 g KCl / 39.10 g K) = 2.50 g KCl
Therefore, 2.50 g of K will produce 2.50 g of KCl.